Change precedence order for continue and legacy exact match

This doesn't matter for shouldDelegateList, but matters when picking
source of RV. RV from continue takes precedence.

Kubernetes-commit: 7da942ca7486310893d4f11f3af062957f953555
This commit is contained in:
Marek Siarkowicz 2025-03-19 13:58:43 +01:00 committed by Kubernetes Publisher
parent dfc7cb5fe1
commit 91724cfd41
2 changed files with 8 additions and 8 deletions

View File

@ -257,14 +257,14 @@ func shouldDelegateList(opts storage.ListOptions, cache delegator.Helper) (deleg
case metav1.ResourceVersionMatchNotOlderThan:
return delegator.Result{ShouldDelegate: false}, nil
case "":
// Legacy exact match
if opts.Predicate.Limit > 0 && len(opts.ResourceVersion) > 0 && opts.ResourceVersion != "0" {
return cache.ShouldDelegateExactRV(opts.ResourceVersion, opts.Recursive)
}
// Continue
if len(opts.Predicate.Continue) > 0 {
return cache.ShouldDelegateContinue(opts.Predicate.Continue, opts.Recursive)
}
// Legacy exact match
if opts.Predicate.Limit > 0 && len(opts.ResourceVersion) > 0 && opts.ResourceVersion != "0" {
return cache.ShouldDelegateExactRV(opts.ResourceVersion, opts.Recursive)
}
// Consistent Read
if opts.ResourceVersion == "" {
return cache.ShouldDelegateConsistentRead()

View File

@ -172,14 +172,14 @@ func shouldDelegateList(opts *metav1.ListOptions, cache delegator.Helper) (deleg
case metav1.ResourceVersionMatchNotOlderThan:
return delegator.Result{ShouldDelegate: false}, nil
case "":
// Legacy exact match
if opts.Limit > 0 && len(opts.ResourceVersion) > 0 && opts.ResourceVersion != "0" {
return cache.ShouldDelegateExactRV(opts.ResourceVersion, defaultRecursive)
}
// Continue
if len(opts.Continue) > 0 {
return cache.ShouldDelegateContinue(opts.Continue, defaultRecursive)
}
// Legacy exact match
if opts.Limit > 0 && len(opts.ResourceVersion) > 0 && opts.ResourceVersion != "0" {
return cache.ShouldDelegateExactRV(opts.ResourceVersion, defaultRecursive)
}
// Consistent Read
if opts.ResourceVersion == "" {
return cache.ShouldDelegateConsistentRead()