Merge pull request #1241 from TingFeng-Git/master
更新 0435 无重叠区间 java版本右边界解法中排序的判断逻辑
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@ -184,13 +184,14 @@ public:
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class Solution {
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public int eraseOverlapIntervals(int[][] intervals) {
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Arrays.sort(intervals, (a, b) -> {
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if (a[0] == a[0]) return a[1] - b[1];
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return a[0] - b[0];
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// 按照区间右边界升序排序
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return a[1] - b[1];
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});
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int count = 0;
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int edge = Integer.MIN_VALUE;
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for (int i = 0; i < intervals.length; i++) {
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// 若上一个区间的右边界小于当前区间的左边界,说明无交集
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if (edge <= intervals[i][0]) {
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edge = intervals[i][1];
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} else {
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