Update 0203.移除链表元素.md
Typo : std::men::replace -> std::mem::replace
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@ -545,7 +545,7 @@ impl Solution {
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let mut dummyHead = Box::new(ListNode::new(0));
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dummyHead.next = head;
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let mut cur = dummyHead.as_mut();
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// 使用take()替换std::men::replace(&mut node.next, None)达到相同的效果,并且更普遍易读
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// 使用take()替换std::mem::replace(&mut node.next, None)达到相同的效果,并且更普遍易读
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while let Some(nxt) = cur.next.take() {
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if nxt.val == val {
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cur.next = nxt.next;
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