# 小美的排列询问

模拟题，注意 x 和y 不分先后

```CPP 

#include <iostream>
#include <vector>
using namespace std;
int main() {
    int n, x, y;
    cin >> n;
    vector<int> vec(n, 0);
    for (int i =0; i < n; i++) {
        cin >> vec[i];
    }
    cin >> x >> y;
    for (int i = 0; i < n - 1; i++) {
        if (x == vec[i] && y == vec[i + 1]) || (y == vec[i] && x == vec[i + 1]) ) {
            cout << "Yes" << endl;
            return 0;
        }
    }
    cout << "No" << endl;

}

```