feat: add solutions to lc/lcof2 problem: Subsets

This commit is contained in:
yanglbme 2021-10-01 15:36:27 +08:00
parent 3db198bc35
commit c5df5c4f3c
12 changed files with 372 additions and 89 deletions

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@ -8,6 +8,7 @@ on:
- "**.jpeg"
- "**.png"
- "**.webp"
workflow_dispatch:
jobs:
compress:

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@ -43,6 +43,23 @@
<!-- 这里可写通用的实现逻辑 -->
回溯法的基本模板:
```py
res = []
path = []
def backtrack(未探索区域, res, path):
if path 满足条件:
res.add(path) # 深度拷贝
# return # 如果不用继续搜索需要 return
for 选择 in 未探索区域当前可能的选择:
if 当前选择符合要求:
path.add(当前选择)
backtrack(新的未探索区域, res, path)
path.pop()
```
<!-- tabs:start -->
### **Python3**
@ -50,7 +67,21 @@
<!-- 这里可写当前语言的特殊实现逻辑 -->
```python
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
res = []
def dfs(i, n, t):
res.append(t.copy())
if i == n:
return
for j in range(i, n):
t.append(nums[j])
dfs(j + 1, n, t)
t.pop()
dfs(0, len(nums), [])
return res
```
### **Java**
@ -58,7 +89,75 @@
<!-- 这里可写当前语言的特殊实现逻辑 -->
```java
class Solution {
public List<List<Integer>> subsets(int[] nums) {
List<List<Integer>> res = new ArrayList<>();
dfs(0, nums, new ArrayList<>(), res);
return res;
}
private void dfs(int i, int[] nums, List<Integer> t, List<List<Integer>> res) {
res.add(new ArrayList<>(t));
if (i == nums.length) {
return;
}
for (int j = i; j < nums.length; ++j) {
t.add(nums[j]);
dfs(j + 1, nums, t, res);
t.remove(t.size() - 1);
}
}
}
```
### **C++**
```cpp
class Solution {
public:
vector<vector<int>> subsets(vector<int>& nums) {
vector<vector<int>> res;
vector<int> t;
dfs(0, nums, t, res);
return res;
}
void dfs(int i, vector<int>& nums, vector<int> t, vector<vector<int>>& res) {
res.push_back(t);
if (i == nums.size()) return;
for (int j = i; j < nums.size(); ++j)
{
t.push_back(nums[j]);
dfs(j + 1, nums, t, res);
t.pop_back();
}
}
};
```
### **Go**
```go
func subsets(nums []int) [][]int {
var res [][]int
var t []int
dfs(0, nums, t, &res)
return res
}
func dfs(i int, nums, t []int, res *[][]int) {
cp := make([]int, len(t))
copy(cp, t)
*res = append(*res, cp)
if i == len(nums) {
return
}
for j := i; j < len(nums); j++ {
t = append(t, nums[j])
dfs(j+1, nums, t, res)
t = t[:len(t)-1]
}
}
```
### **...**

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@ -0,0 +1,20 @@
class Solution {
public:
vector<vector<int>> subsets(vector<int>& nums) {
vector<vector<int>> res;
vector<int> t;
dfs(0, nums, t, res);
return res;
}
void dfs(int i, vector<int>& nums, vector<int> t, vector<vector<int>>& res) {
res.push_back(t);
if (i == nums.size()) return;
for (int j = i; j < nums.size(); ++j)
{
t.push_back(nums[j]);
dfs(j + 1, nums, t, res);
t.pop_back();
}
}
};

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@ -0,0 +1,20 @@
func subsets(nums []int) [][]int {
var res [][]int
var t []int
dfs(0, nums, t, &res)
return res
}
func dfs(i int, nums, t []int, res *[][]int) {
cp := make([]int, len(t))
copy(cp, t)
*res = append(*res, cp)
if i == len(nums) {
return
}
for j := i; j < len(nums); j++ {
t = append(t, nums[j])
dfs(j+1, nums, t, res)
t = t[:len(t)-1]
}
}

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@ -0,0 +1,19 @@
class Solution {
public List<List<Integer>> subsets(int[] nums) {
List<List<Integer>> res = new ArrayList<>();
dfs(0, nums, new ArrayList<>(), res);
return res;
}
private void dfs(int i, int[] nums, List<Integer> t, List<List<Integer>> res) {
res.add(new ArrayList<>(t));
if (i == nums.length) {
return;
}
for (int j = i; j < nums.length; ++j) {
t.add(nums[j]);
dfs(j + 1, nums, t, res);
t.remove(t.size() - 1);
}
}
}

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@ -0,0 +1,15 @@
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
res = []
def dfs(i, n, t):
res.append(t.copy())
if i == n:
return
for j in range(i, n):
t.append(nums[j])
dfs(j + 1, n, t)
t.pop()
dfs(0, len(nums), [])
return res

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@ -36,7 +36,6 @@
<li><code>nums</code> 中的所有元素 <strong>互不相同</strong></li>
</ul>
## 解法
<!-- 这里可写通用的实现逻辑 -->
@ -67,15 +66,18 @@ def backtrack(未探索区域, res, path):
```python
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
def dfs(nums, i, res, path):
res.append(copy.deepcopy(path))
while i < len(nums):
path.append(nums[i])
dfs(nums, i + 1, res, path)
path.pop()
i += 1
res, path = [], []
dfs(nums, 0, res, path)
res = []
def dfs(i, n, t):
res.append(t.copy())
if i == n:
return
for j in range(i, n):
t.append(nums[j])
dfs(j + 1, n, t)
t.pop()
dfs(0, len(nums), [])
return res
```
@ -86,24 +88,75 @@ class Solution:
```java
class Solution {
public List<List<Integer>> subsets(int[] nums) {
List<Integer> path = new ArrayList<>();
List<List<Integer>> res = new ArrayList<>();
dfs(nums, 0, res, path);
dfs(0, nums, new ArrayList<>(), res);
return res;
}
private void dfs(int[] nums, int i, List<List<Integer>> res, List<Integer> path) {
res.add(new ArrayList<>(path));
while (i < nums.length) {
path.add(nums[i]);
dfs(nums, i + 1, res, path);
path.remove(path.size() - 1);
++i;
private void dfs(int i, int[] nums, List<Integer> t, List<List<Integer>> res) {
res.add(new ArrayList<>(t));
if (i == nums.length) {
return;
}
for (int j = i; j < nums.length; ++j) {
t.add(nums[j]);
dfs(j + 1, nums, t, res);
t.remove(t.size() - 1);
}
}
}
```
### **C++**
```cpp
class Solution {
public:
vector<vector<int>> subsets(vector<int>& nums) {
vector<vector<int>> res;
vector<int> t;
dfs(0, nums, t, res);
return res;
}
void dfs(int i, vector<int>& nums, vector<int> t, vector<vector<int>>& res) {
res.push_back(t);
if (i == nums.size()) return;
for (int j = i; j < nums.size(); ++j)
{
t.push_back(nums[j]);
dfs(j + 1, nums, t, res);
t.pop_back();
}
}
};
```
### **Go**
```go
func subsets(nums []int) [][]int {
var res [][]int
var t []int
dfs(0, nums, t, &res)
return res
}
func dfs(i int, nums, t []int, res *[][]int) {
cp := make([]int, len(t))
copy(cp, t)
*res = append(*res, cp)
if i == len(nums) {
return
}
for j := i; j < len(nums); j++ {
t = append(t, nums[j])
dfs(j+1, nums, t, res)
t = t[:len(t)-1]
}
}
```
### **...**
```

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@ -32,9 +32,10 @@
<li>All the numbers of&nbsp;<code>nums</code> are <strong>unique</strong>.</li>
</ul>
## Solutions
DFS.
<!-- tabs:start -->
### **Python3**
@ -42,15 +43,18 @@
```python
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
def dfs(nums, i, res, path):
res.append(copy.deepcopy(path))
while i < len(nums):
path.append(nums[i])
dfs(nums, i + 1, res, path)
path.pop()
i += 1
res, path = [], []
dfs(nums, 0, res, path)
res = []
def dfs(i, n, t):
res.append(t.copy())
if i == n:
return
for j in range(i, n):
t.append(nums[j])
dfs(j + 1, n, t)
t.pop()
dfs(0, len(nums), [])
return res
```
@ -59,24 +63,75 @@ class Solution:
```java
class Solution {
public List<List<Integer>> subsets(int[] nums) {
List<Integer> path = new ArrayList<>();
List<List<Integer>> res = new ArrayList<>();
dfs(nums, 0, res, path);
dfs(0, nums, new ArrayList<>(), res);
return res;
}
private void dfs(int[] nums, int i, List<List<Integer>> res, List<Integer> path) {
res.add(new ArrayList<>(path));
while (i < nums.length) {
path.add(nums[i]);
dfs(nums, i + 1, res, path);
path.remove(path.size() - 1);
++i;
private void dfs(int i, int[] nums, List<Integer> t, List<List<Integer>> res) {
res.add(new ArrayList<>(t));
if (i == nums.length) {
return;
}
for (int j = i; j < nums.length; ++j) {
t.add(nums[j]);
dfs(j + 1, nums, t, res);
t.remove(t.size() - 1);
}
}
}
```
### **C++**
```cpp
class Solution {
public:
vector<vector<int>> subsets(vector<int>& nums) {
vector<vector<int>> res;
vector<int> t;
dfs(0, nums, t, res);
return res;
}
void dfs(int i, vector<int>& nums, vector<int> t, vector<vector<int>>& res) {
res.push_back(t);
if (i == nums.size()) return;
for (int j = i; j < nums.size(); ++j)
{
t.push_back(nums[j]);
dfs(j + 1, nums, t, res);
t.pop_back();
}
}
};
```
### **Go**
```go
func subsets(nums []int) [][]int {
var res [][]int
var t []int
dfs(0, nums, t, &res)
return res
}
func dfs(i int, nums, t []int, res *[][]int) {
cp := make([]int, len(t))
copy(cp, t)
*res = append(*res, cp)
if i == len(nums) {
return
}
for j := i; j < len(nums); j++ {
t = append(t, nums[j])
dfs(j+1, nums, t, res)
t = t[:len(t)-1]
}
}
```
### **...**
```

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@ -1,22 +1,20 @@
class Solution {
public:
vector<vector<int>> subsets(vector<int>& nums) {
vector<vector<int>> ans;
vector<int> tmp;
int n = nums.size();
dfs(ans,nums,tmp,0,n);
return ans;
vector<vector<int>> res;
vector<int> t;
dfs(0, nums, t, res);
return res;
}
void dfs(vector<vector<int>> &ans,vector<int>& nums,vector<int> &tmp,int k,int n){
ans.push_back(tmp);
for(int i = k;i < n;i++)
void dfs(int i, vector<int>& nums, vector<int> t, vector<vector<int>>& res) {
res.push_back(t);
if (i == nums.size()) return;
for (int j = i; j < nums.size(); ++j)
{
tmp.push_back(nums[i]);
dfs(ans,nums,tmp,i+1,n);
tmp.pop_back();
t.push_back(nums[j]);
dfs(j + 1, nums, t, res);
t.pop_back();
}
}
};

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@ -1,21 +1,20 @@
func subsets(nums []int) [][]int {
n := len(nums)
ans := make([][]int,0)
tmp := make([]int,0)
dfs(&ans,tmp,nums,0,n)
return ans
var res [][]int
var t []int
dfs(0, nums, t, &res)
return res
}
func dfs(ans *[][]int,tmp []int,nums []int,k,n int) {
tmpVec := make([]int,len(tmp))
copy(tmpVec,tmp)
*ans = append(*ans,tmpVec)
for i:=k;i < n;i++{
tmp = append(tmp,nums[i])
dfs(ans,tmp,nums,i+1,n)
tmp = tmp[:len(tmp) - 1]
}
}
func dfs(i int, nums, t []int, res *[][]int) {
cp := make([]int, len(t))
copy(cp, t)
*res = append(*res, cp)
if i == len(nums) {
return
}
for j := i; j < len(nums); j++ {
t = append(t, nums[j])
dfs(j+1, nums, t, res)
t = t[:len(t)-1]
}
}

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@ -1,18 +1,19 @@
class Solution {
public List<List<Integer>> subsets(int[] nums) {
List<Integer> path = new ArrayList<>();
List<List<Integer>> res = new ArrayList<>();
dfs(nums, 0, res, path);
dfs(0, nums, new ArrayList<>(), res);
return res;
}
private void dfs(int[] nums, int i, List<List<Integer>> res, List<Integer> path) {
res.add(new ArrayList<>(path));
while (i < nums.length) {
path.add(nums[i]);
dfs(nums, i + 1, res, path);
path.remove(path.size() - 1);
++i;
private void dfs(int i, int[] nums, List<Integer> t, List<List<Integer>> res) {
res.add(new ArrayList<>(t));
if (i == nums.length) {
return;
}
for (int j = i; j < nums.length; ++j) {
t.add(nums[j]);
dfs(j + 1, nums, t, res);
t.remove(t.size() - 1);
}
}
}

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@ -1,12 +1,15 @@
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
def dfs(nums, i, res, path):
res.append(copy.deepcopy(path))
while i < len(nums):
path.append(nums[i])
dfs(nums, i + 1, res, path)
path.pop()
i += 1
res, path = [], []
dfs(nums, 0, res, path)
return res
res = []
def dfs(i, n, t):
res.append(t.copy())
if i == n:
return
for j in range(i, n):
t.append(nums[j])
dfs(j + 1, n, t)
t.pop()
dfs(0, len(nums), [])
return res