leetcode/lcci/02.04.Partition List/Solution.go

23 lines
451 B
Go

/**
* Definition for singly-linked list.
* type ListNode struct {
* Val int
* Next *ListNode
* }
*/
func partition(head *ListNode, x int) *ListNode {
left, right := &ListNode{}, &ListNode{}
p1, p2 := left, right
for ; head != nil; head = head.Next {
if head.Val < x {
p1.Next = head
p1 = p1.Next
} else {
p2.Next = head
p2 = p2.Next
}
}
p1.Next = right.Next
p2.Next = nil
return left.Next
}