leetcode/solution/0200-0299/0209.Minimum Size Subarray Sum/Solution.java

30 lines
771 B
Java

class Solution {
public int minSubArrayLen(int target, int[] nums) {
int n = nums.length;
long[] s = new long[n + 1];
for (int i = 0; i < n; ++i) {
s[i + 1] = s[i] + nums[i];
}
int ans = n + 1;
for (int i = 0; i <= n; ++i) {
int j = search(s, s[i] + target);
if (j <= n) {
ans = Math.min(ans, j - i);
}
}
return ans <= n ? ans : 0;
}
private int search(long[] nums, long x) {
int l = 0, r = nums.length;
while (l < r) {
int mid = (l + r) >> 1;
if (nums[mid] >= x) {
r = mid;
} else {
l = mid + 1;
}
}
return l;
}
}